BD Merit - Freelancing, BCS, Bank, Primary, Admission, NTRCA

1 . 64 23+62512=3k

View Answer

Workspace

Report

Answer: Option D

Explanation:

(64) \frac{2}{3} + (625) \frac{1}{2} = 3 k \Rightarrow (4^{3}) \frac{2}{3} + \{{(25)}^{2}\} \frac{1}{2} = 3 k \Rightarrow 4^{2} + 25 = 3 k \Rightarrow 16 + 25 = 3 k \Rightarrow 41 = 3 k \Rightarrow k = \frac{41}{3} = 13 \frac{2}{3}